Síntese e caracterização de compostos diorganoestânicos com ácido dl-mandélico
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Por reação de quantidades eqüimoleculares de R2SnO ou R2SnCl2 (R = -CH3; -C4H9) com ácido dl-mandélico, C6H5CH(OH)COOH, em meio de etanol, foram obtidos novos compostos formulados como [(LR2Sn)2O] [L= C6H5CH(OH)COO-], nos quais o átomo de estanho é pentacoordenado, com o ligante L estabelecendo uma ligação bidentada através dos átomos de oxigênio dos grupos ácido e hidroxila alcoólica. Nas mesmas condições, nenhum produto obtido a partir da reação de (C6H5)2SnO ou (C6H5)2SnCl2 pode ser identificado. No entanto, quando da reação de (C6H5)2SnCl2 com ácido dl-mandélico, em meio de acetonitrila, foi preparado um composto dimérico hexacoordenado formulado como [L(C6H5)2SnCl]2. Este composto não pode ser isolado de forma pura e está misturado com 7% de impurezas não identificadas, cujos parâmetros de interação hiperfina sugerem tratar de estanho tetravalente octaedricamente coordenado por oxigênio. Os compostos obtidos foram caracterizados por determinação de ponto de fusão, microanálise e espectroscopias i.v. e Mössbauer.
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